3.2.50 \(\int x^3 \sqrt {a+a \cos (x)} \, dx\) [150]

Optimal. Leaf size=68 \[ -96 \sqrt {a+a \cos (x)}+12 x^2 \sqrt {a+a \cos (x)}-48 x \sqrt {a+a \cos (x)} \tan \left (\frac {x}{2}\right )+2 x^3 \sqrt {a+a \cos (x)} \tan \left (\frac {x}{2}\right ) \]

[Out]

-96*(a+a*cos(x))^(1/2)+12*x^2*(a+a*cos(x))^(1/2)-48*x*(a+a*cos(x))^(1/2)*tan(1/2*x)+2*x^3*(a+a*cos(x))^(1/2)*t
an(1/2*x)

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Rubi [A]
time = 0.07, antiderivative size = 68, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {3400, 3377, 2718} \begin {gather*} 2 x^3 \tan \left (\frac {x}{2}\right ) \sqrt {a \cos (x)+a}+12 x^2 \sqrt {a \cos (x)+a}-96 \sqrt {a \cos (x)+a}-48 x \tan \left (\frac {x}{2}\right ) \sqrt {a \cos (x)+a} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^3*Sqrt[a + a*Cos[x]],x]

[Out]

-96*Sqrt[a + a*Cos[x]] + 12*x^2*Sqrt[a + a*Cos[x]] - 48*x*Sqrt[a + a*Cos[x]]*Tan[x/2] + 2*x^3*Sqrt[a + a*Cos[x
]]*Tan[x/2]

Rule 2718

Int[sin[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-Cos[c + d*x]/d, x] /; FreeQ[{c, d}, x]

Rule 3377

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> Simp[(-(c + d*x)^m)*(Cos[e + f*x]/f), x]
+ Dist[d*(m/f), Int[(c + d*x)^(m - 1)*Cos[e + f*x], x], x] /; FreeQ[{c, d, e, f}, x] && GtQ[m, 0]

Rule 3400

Int[((c_.) + (d_.)*(x_))^(m_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Dist[(2*a)^IntPart[n]
*((a + b*Sin[e + f*x])^FracPart[n]/Sin[e/2 + a*(Pi/(4*b)) + f*(x/2)]^(2*FracPart[n])), Int[(c + d*x)^m*Sin[e/2
+ a*(Pi/(4*b)) + f*(x/2)]^(2*n), x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[a^2 - b^2, 0] && IntegerQ[n
+ 1/2] && (GtQ[n, 0] || IGtQ[m, 0])

Rubi steps

\begin {align*} \int x^3 \sqrt {a+a \cos (x)} \, dx &=\left (\sqrt {a+a \cos (x)} \sec \left (\frac {x}{2}\right )\right ) \int x^3 \cos \left (\frac {x}{2}\right ) \, dx\\ &=2 x^3 \sqrt {a+a \cos (x)} \tan \left (\frac {x}{2}\right )-\left (6 \sqrt {a+a \cos (x)} \sec \left (\frac {x}{2}\right )\right ) \int x^2 \sin \left (\frac {x}{2}\right ) \, dx\\ &=12 x^2 \sqrt {a+a \cos (x)}+2 x^3 \sqrt {a+a \cos (x)} \tan \left (\frac {x}{2}\right )-\left (24 \sqrt {a+a \cos (x)} \sec \left (\frac {x}{2}\right )\right ) \int x \cos \left (\frac {x}{2}\right ) \, dx\\ &=12 x^2 \sqrt {a+a \cos (x)}-48 x \sqrt {a+a \cos (x)} \tan \left (\frac {x}{2}\right )+2 x^3 \sqrt {a+a \cos (x)} \tan \left (\frac {x}{2}\right )+\left (48 \sqrt {a+a \cos (x)} \sec \left (\frac {x}{2}\right )\right ) \int \sin \left (\frac {x}{2}\right ) \, dx\\ &=-96 \sqrt {a+a \cos (x)}+12 x^2 \sqrt {a+a \cos (x)}-48 x \sqrt {a+a \cos (x)} \tan \left (\frac {x}{2}\right )+2 x^3 \sqrt {a+a \cos (x)} \tan \left (\frac {x}{2}\right )\\ \end {align*}

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Mathematica [A]
time = 0.04, size = 33, normalized size = 0.49 \begin {gather*} 2 \sqrt {a (1+\cos (x))} \left (6 \left (-8+x^2\right )+x \left (-24+x^2\right ) \tan \left (\frac {x}{2}\right )\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^3*Sqrt[a + a*Cos[x]],x]

[Out]

2*Sqrt[a*(1 + Cos[x])]*(6*(-8 + x^2) + x*(-24 + x^2)*Tan[x/2])

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Maple [C] Result contains complex when optimal does not.
time = 0.07, size = 87, normalized size = 1.28

method	result	size
risch	\(-\frac {i \sqrt {2}\, \sqrt {a \left ({\mathrm e}^{i x}+1\right )^{2} {\mathrm e}^{-i x}}\, \left (6 i x^{2} {\mathrm e}^{i x}+x^{3} {\mathrm e}^{i x}+6 i x^{2}-x^{3}-48 i {\mathrm e}^{i x}-24 x \,{\mathrm e}^{i x}-48 i+24 x \right )}{{\mathrm e}^{i x}+1}\)	\(87\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(a+a*cos(x))^(1/2),x,method=_RETURNVERBOSE)

[Out]

-I*2^(1/2)*(a*(exp(I*x)+1)^2*exp(-I*x))^(1/2)/(exp(I*x)+1)*(6*I*x^2*exp(I*x)+x^3*exp(I*x)+6*I*x^2-x^3-48*I*exp
(I*x)-24*x*exp(I*x)-48*I+24*x)

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Maxima [A]
time = 0.51, size = 48, normalized size = 0.71 \begin {gather*} 2 \, {\left (\sqrt {2} x^{3} \sin \left (\frac {1}{2} \, x\right ) + 6 \, \sqrt {2} x^{2} \cos \left (\frac {1}{2} \, x\right ) - 24 \, \sqrt {2} x \sin \left (\frac {1}{2} \, x\right ) - 48 \, \sqrt {2} \cos \left (\frac {1}{2} \, x\right )\right )} \sqrt {a} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+a*cos(x))^(1/2),x, algorithm="maxima")

[Out]

2*(sqrt(2)*x^3*sin(1/2*x) + 6*sqrt(2)*x^2*cos(1/2*x) - 24*sqrt(2)*x*sin(1/2*x) - 48*sqrt(2)*cos(1/2*x))*sqrt(a
)

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Fricas [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+a*cos(x))^(1/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (ha
s polynomial part)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{3} \sqrt {a \left (\cos {\left (x \right )} + 1\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(a+a*cos(x))**(1/2),x)

[Out]

Integral(x**3*sqrt(a*(cos(x) + 1)), x)

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Giac [A]
time = 0.40, size = 55, normalized size = 0.81 \begin {gather*} 2 \, \sqrt {2} {\left (6 \, {\left (x^{2} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, x\right )\right ) - 8 \, \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, x\right )\right )\right )} \cos \left (\frac {1}{2} \, x\right ) + {\left (x^{3} \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, x\right )\right ) - 24 \, x \mathrm {sgn}\left (\cos \left (\frac {1}{2} \, x\right )\right )\right )} \sin \left (\frac {1}{2} \, x\right )\right )} \sqrt {a} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+a*cos(x))^(1/2),x, algorithm="giac")

[Out]

2*sqrt(2)*(6*(x^2*sgn(cos(1/2*x)) - 8*sgn(cos(1/2*x)))*cos(1/2*x) + (x^3*sgn(cos(1/2*x)) - 24*x*sgn(cos(1/2*x)
))*sin(1/2*x))*sqrt(a)

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Mupad [B]
time = 0.43, size = 91, normalized size = 1.34 \begin {gather*} \frac {2\,\sqrt {a}\,\sqrt {\cos \left (x\right )+1}\,\left (24\,x-\cos \left (x\right )\,48{}\mathrm {i}+48\,\sin \left (x\right )+x^2\,\cos \left (x\right )\,6{}\mathrm {i}+x^3\,\cos \left (x\right )-6\,x^2\,\sin \left (x\right )+x^3\,\sin \left (x\right )\,1{}\mathrm {i}-24\,x\,\cos \left (x\right )-x\,\sin \left (x\right )\,24{}\mathrm {i}+x^2\,6{}\mathrm {i}-x^3-48{}\mathrm {i}\right )}{\cos \left (x\right )\,1{}\mathrm {i}-\sin \left (x\right )+1{}\mathrm {i}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(a + a*cos(x))^(1/2),x)

[Out]

(2*a^(1/2)*(cos(x) + 1)^(1/2)*(24*x - cos(x)*48i + 48*sin(x) + x^2*cos(x)*6i + x^3*cos(x) - 6*x^2*sin(x) + x^3
*sin(x)*1i - 24*x*cos(x) - x*sin(x)*24i + x^2*6i - x^3 - 48i))/(cos(x)*1i - sin(x) + 1i)

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